In the code shown above, the value for first is substituted by l[0], that is H and the value for third is substituted by l[2], that is L. Hence the output of the code shown above is: ‘first=H, third=L’. The list l= [‘H’, ‘E’, ‘L’, ‘L’, ‘O’].
In the code shown above, the value for first is substituted by l[0], that is H and the value for third is substituted by l[2], that is L. Hence the output of the code shown above is: ‘first=H, third=L’. The list l= [‘H’, ‘E’, ‘L’, ‘L’, ‘O’].